def filtro(n):
    return n % 2
l1 = [1, 1, 2, 99, 22, 77, 77, 77, 2, 3, 4, 6, 5, 7, 9, 9, 9];
impar = filter(filtro, l1)
it = iter(l1)
for i in it:
    if l1.count(i) > 1:
        l1.remove(i)
print l1
